64-x²>0(8-x)(8+x)>0x=8 x=-8x∈(-8;8)log(4)(64-x²)=aa²-5a+6≥0a1+a2=5 U a1*a2=6a1=2 U a2=3a≤2⇒log(4)(64-x²)≤2⇒64-x²≤16⇒48-x²≤0⇒(4√3-x)(4√3+x)≤0x=4√3 x=-4√3x≤-4√3 U x≥4√3x∈(-8;-4√3] U [4√3;8)a2≥3⇒log(4)(64-x²)≥3⇒64-x²≥64≥x²≤0⇒x=0Ответ x∈(-8;-4√3] U [4√3;8) U {0}