Найти корни:
1)X^2-7x+12
2)x^2+2x-24
3)x^2-3x-108

1. x^2-7x+12=0D=49-4*1*12=49-48=1x1=7+1/2=4x2=7-1/2=32. x^2+2x-24=0D=4-4*(-24)=4+96=100=10x1=-2+10/2=4x2=-2-12/2=-63. x^2-3x-108=0D=9-4*(-108)=9+432=441=21x1=3+21/2=12x2=3-21/2=-9