решить систему уравнений x^3-y^3=56 и x^2+xy+y^2=28

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

1)x³-y³=56x²+xy+y²=282)    |(x-y)(x²+xy+y²)=56    ÷ |x²+xy+y²=28______________________(x-y)(x²+xy+y²)/x²+xy+y²=56/28x-y=2x=2+y3) x=2+y(2+y)³-y³=56(2+y-y)[(2+y)²+(2+y)y+y²)=564+4y+y²+2y+y²+y²=283y²+6y-24=0y²+2y-12=0k=1D=1+24=25y1=-6  y2=44)y=-6x=2-6=-4y=4x=2-4=-2ответ:(-4;-6);(-2;4)