Помогите с тригонометрией,очень надо,решающая оценка

1x/3=π/2+πn,n∈z⇒x=3π/2+3πn,n∈z23x/4-π/4=π/4+πn,n∈z3x/4=π/2+πn,n∈zx=2π/3+4πn/3,n∈z3sin(3x+π/3)=-√3/23x+π/3=(-1)^(n+1)*π/3+πn,n∈z3x=-π/3+(-1)^(n+1)*π/3+πn,n∈zx-π/9+(-1)^(n+1)*π/9+πn/3,n∈z4{cosx≠√3/2{sinx=-1/2x=7π/6+2πn,n∈z5{sinx≠-√3/2{cosx=1/2x=π/6+2πn6{cos2x≠1{cos3x=03x=π/2+πn,n∈zx=π/6+πn/3,n∈z7cos4x=-1⇒4x=π+2πn,n∈z⇒x=π/4+πn/2,n∈zsin2x=0⇒2x=πk⇒x=πk/2,k∈z8cos(x+π/4)=-1⇒x+π/4=π+2πn,n∈z⇒x=3π/4+2πn,n∈ztgx=-1⇒x=-π/4+πk,k∈z