Решите уравнение cosxcos3x=0,5

1/2(cos2x+cos4x)=1/2cos2x+2cos²2x-1=0cos2x=a2a²+a-1=0D=1+8=9a1=(-1-3)/4=-1⇒cos2x=-1⇒2x=π+2πn,n∈z⇒x=π/2+πn,n∈za2=(-1+3)/4=1/2⇒cos2x=1/2⇒2x=+-π/3+2πk,k∈z⇒x=π/6+πk,k∈z