прошу,помогите решить уравнение х^2-3√2х+4

D = (3√2)² - 4*1*4 = 18 - 16 = 2x_1 = (3√2 - √2) / 2 = 2√2 / 2 = √2x_2 = (3√2 + √2) / 2 = 4√2 / 2 = 2√2

a=1; b = -3√2 ;c=4D=b²-4ac=18 -16=2√D=√2x₁= (3√2+√2):2= √2(3+1):2= 4√2:2=2√2x₂= (3√2-√2):2=√2(3-1):2=2√2:2=√2