log1/9(7-2x)=-2.решите уравнение

ОДЗ: 7-2х>0-2x>-7x<3,5Log1/9(7-2x)=-(log1/9(1/9)+log1/9(1/9))Log1/9(7-2x)=-log1/9(1/81)Log1/9(7-2x)=log1/9(81)7-2x=81-2x=81-7-2x=74х=-37