Помогите решить пожалуйста!)
1)45 / sin( – 25 × π / 4) × cos(35 × π / 4)
2)4 × sin(130°) / sin(65°) × sin(25°)
3)– 14 × sin(58°) / cos(29°) × cos(61°)
4)tg^2-? 4sin^2a+10cos^2a=9

Спасибо огромное!)

1)45 / sin( – 25 × π / 4) × cos(35 × π / 4) =45/(-sin(6π+π/4)*cos(9π-π/4))==45/(-sinπ/4*(-cosπ/4)=90/sinπ/2=902)4 × sin(130°) / sin(65°) × sin(25°) =4sin(180-50)/(sin(90-25)sin25)==4sin50/(cos25sin25)=8sin50/sin50=83)– 14 × sin(58°) / cos(29°) × cos(61°) =-14sin58/(cos29cos(90-29))==-14sin58/(cos29sin29)=-28sin58/sin58=-284)tg^2-? 4sin^2a+10cos^2a=94sin²a+10-10sin²a=96sin²a=1sin²a-1/6cos²a=1-sin²a=1-1/6=5/6tg²a=sin²a/cos²a=1/6:5/6=1/6*6/5=1/5