Решите пожалуйста :
(x-4)^2*(x+10)=15*(x-4)

( x - 4)^2 * (x + 10) - 15(x - 4) = 0( x - 4)( (x-4)(x+10) - 15) =0(x - 4)( x^2+ 6x - 40 - 15) = 0( x - 4)(x^2 + 6x - 55) = 0x - 4 = 0x = 4x^2 + 6x - 55 = 0D = b^2 - 4ac = 36 + 220= 256 =16^2x1 = ( - 6 + 16) / 2 = 5x2 = ( - 6 - 16) / 2 = - 11Ответ: x1 = 5, x2 = - 11, x3 = 4.