Помогите решить систему уравнений:

14*49^x - 18*14^x - y = 0
y + 4^(x+1) = 0

у = 14*49^x - 18*14^xy = -4^(x+1)14*49^x - 18*14^x= -4^(x+1)14*49^x - 18*14^x + 4^(x+1) = 014*(7²)^x - 18*(7*2)^x + (2²)^(x+1)=014*(7²)^x - 18*(7*2)^x + (2²)^x * (2²)^1 = 014*(7²)^x - 18*(7*2)^x + 4* (2²)^x = 0 | : (2²)^x ≠ 014*(7/2)^2x -18*(7/2)^x +4 = 0(7/2)^x = t14t² -18t +4 = 0t = (9+-√81 - 56)/14 = (9 +-5)/14t1 = 1                 t2 = 4/14 = 2/7(7/)^x = 1           (7/2)^x = 2/7x = 0                   x = -1