7log(2)9=a(a²-2a+2(a+1)²-3a(a+1)+4*(a+1))/(a-2(a+1))==(a²-2a+2a²+4a+2-3a²-3a+4a+4)/(a-2a-2)=(3a+6)/(-a-2)==3(a+2)/(-(a+2))=-310Перейдем к логарифму по основанию b(1/3-log(b)√a)/(1-log(b)∛a) +3(log(b)√a+1/2)/(1-log(b)∛a)==(1/3-1/2*log(b)a+3/2*log(b)a+3/2)/(1-1/3*log(b)a)==(log(b)a+7/6)/(1-1/3*log(b)a)=(2+7/6)/(1-2/3)=19/6*3/1=19/2=9,5