Решите пожалуйста))!!!

[tex] 14^{x}+7= 2^{x} +7^{x+1}[/tex]

Решение14^x + 7 = 2^x + 7^(x + 1)(2^x)*(7^x) + 7 - (2^x) - (7^x)*7 = 0(7^x)*(2^x - 7) - (2^x - 7) = 0(2^x  - 7)*(7^x - 1) = 01)  2^x - 7 = 03^x = 7log₃ (3^x) = log₃ 7x₁ = log₃ 72)  7^x - 1 = 07^x = 17^x = 7⁰x₂ = 0