(log_0,5(x^2))/(log_0,5(1/4x))>=log_0,5(x^2)

ОДЗ x>0log(0,5)(0,25x)=log(0,5)0,25+log(0,5)x=2+log(0,5)xlog(0,5)x²=2log(0,5)xlog(0,5)x=a2a/(2+a)-2a≥0(2a-4a-2a²)/(2+a)≥0(-2a-2a²)/(2+a)≥02a(1+a)/(2+a)≤0a=0  a=-1  a=-2            _               +                _                 +--------------(-2)---------[-1]------------[0]-----------------a<-2⇒log(0,5)x<-2⇒x>4-1≤a≤0⇒-1≤log(0,5)x≤0⇒1≤x≤2Ответ x∈[1;2] U (4;∞)