(x-3)(x+1)=(x-2)
Решить.

( x - 3)(x + 1) = ( x - 2)x^2 - 2x - 3 - x + 2 = 0x^2 - 3x - 1 = 0D = b^2 - 4ac = 9 + 4 = 13x1,2 = ( 3 +/- √13)/ 2