Решите пожалуйста
-x - 3x + 10 =0
100 - x^2 =0
-2x^2 =0
13 - x^2 =0
x^2 - 12x + 33 =0
-x^2 + x + 12 = 0
x^2 - 12x + 36 = 0
x^2 + 4x + 20 = 0

- 4x = - 104x = 10x = 2,5- x^2 = - 100x^2 = 100x = 10x = - 10- 2x^2 = 0x^2 = 0x =0- x^2 = - 13x^2 = 13x = √13x = - √13x^2 - 12x + 33 = 0D = b^2 - 4ac = 144 - 132 = 12x1,2 = ( 12+/-√12) / 2x^2 - x - 12 =0D = b^2 - 4ac = 1 + 48 = 49 = 7^2x1 = ( 1 + 7) / 2 = 4x2 = ( 1 - 7) / 2 = - 3x^2 - 12x + 36 = 0D = b^2 - 4ac = 144 - 144 = 0 - имеет один кореньx = - b/2ax = 12/2 = 6x = 6x^2 + 4x + 20 = 0D = b^2 - 4ac = 16 - 80 = - 64 - дискиминант отрицательный,значит,корней нет.