. Решите уравнение: 1/(x+1)-3/(x-1)=-2/(x^2-1).

1*(х-1)/(х+1)(х-1) - 3*(х+1)/(х-1)(х+1) = -2/(х-1)(х+1)((х-1) - 3(х+1))/ (х-1)(х+1) = -2/ (х-1)(х+1)х-1-3х-3=-2-2х-4=-2-2х=-2+4-2х=2 х=-1