[tex]( x+ \frac{3- x^{2} }{x-1} ) : \frac{x-3}{1- x^{2} } [/tex]

1)x+(3-x²)/(x-1)=(x²-x+3-x²)/(x-1)=(3-x)/(x-1)2)(3-x)/(x-1):(x-3)/(1-x²)=(x-3)/(1-x)*(1-x)(1+x)/(x-3)=1+x