Помогите решить уравнение:
(х-4)²(х-3)=0
(х²-4)(х+1)=0
х(х²+4)(х+4)=0
(х-5)(х³+1)=0

( x - 4)^2(x- 3) = 0x - 4 = 0x = 4x - 3 = 0x = 3(x^2 - 4)(x + 1) = 0x^2 - 4 = 0x^2 = 4x = 2x = - 2x+ 1 = 0x = - 1x(x^2 + 4)(x + 4) = 0x = 0x^2 + 4 = 0x^2 = - 4 - корней нетx + 4 = 0x = - 4( x - 5)(x^3 + 1) = 0x - 5 = 0x = 5x^3 + 1 = 0x^3 = - 1x = - 1