Решите
cos(0,5П-2х)+sinx=0

sin2x+sinx=02sin(3x/2)cos(x/2)=0sin(3x/2)=0⇒3x/2=πn⇒x=2πn/3,n∈zcos(x/2)/2=0⇒x/2=π/2+πk⇒x=π+2πk,k∈z