Найдите предел функции y = f(x) при x ⇒ [tex]x_{0} [/tex] :
1) [tex]f(x) = \frac{2 x^{2} -4x+2}{3x-3} , x --> 1 [/tex]
2) [tex]f(x) = \frac{ x^{4}-27x+ x^{3} -27 }{3x-9} , x --> 1 [/tex]

1lim[2(x-1)²/3(x-1)]=lim[2(x-1)/3]=2*(1-1)/3=02lim[(x³(x+1)-27(x+1))/(3(x-3))]=lim[(x+1)(x-3)(x²+3x+9)/3(x-3)]==lim[(x+1)(x²+3x+9)/3]=2*13/3=26/3=8 2/3