Решите систему 5(3x-7)-4(2y-3)=20 2x-y-2(y-2)=2

15x-35-8y+12=202x-y-2y+4=215x-8y=35+20-122x-3y=2-415x-8y=432x-3y=-22x=-2+3yx=(-2+3y)/215×(-2+3y)/2-8y=43-15+22.5y-8y=4314,5y=43+1514,5y=58y=58/14.5y=4x=(-2+3×4)/2x=-5