решите уравнение 2х³-5х²-3х=0

x( 2x^2 - 5x - 3) = 0x=02x^2 - 5x - 3 = 0D = b^2 - 4ac = 25 + 24 = 49 = 7^2x1 = ( 5 + 7) / 4 = 3x2 = ( 5 - 7) / 4 = - 0,5Ответ: x1 = 3, x2 = - 0,5, x3 = 0