решите систему уравнений

x+y/2+x-y/3=6
{
x+y/4-x-y/3=6

(x+y)/2+(x-y)/3=6 |*6(x+y)/4-(x-у)/3=6 |*123(x+y)+2(x-y)=363(x+y)-4(x-у)=723х+3у+2х-2у=363х+3у-4х+4у=725х+у=36-х+7у=72у=36-5х-х+7(36-5х)=72-х+252-35х=72-36х=72-252-36х=-180х=-180:(-36)х=5у=36-5ху=36-5*5=36-25=11Ответ: х=5; у=11