найдите значение выражения 36-у^2/у^2-12у+36 при у=3/4

(6-y)(6+y)/(6-y)²=(6+y)/(6-y)y=3/46 3/4: 5 1/4=27/4*4/21=9/7=1 2/7

y²-12y+36=(y-6)²=(6-y)²(6-y)(6+y)/(6-y)² = 6+y/6-yy=3/4  6+3/4=27/4   6-3/4=21/427/4 * 4/21= 27/21=9/7