cosx+(корень из 3)*sinx=sin(x/2-пи/6)

2(1/2*сosx+√3/2*sinx)=sin(x/2-π/6)2сos(x-π/3)=sin(x/2-π/6)x-π/3=2*(x/2-π/6)2*(1-2sin²(x/2-π/6))-sin(x/2-π/6)=0sin(x/2-π/6)=a2-4a²-a=04a²+a-2=0D=1+32=33a1=(-1-√33)/8sin(x/2-π/6)=(-1-√33)/8x/2-π/6=(-1)^(n+1)acrsin[(1+√33)/8]+πnx/2=π/6+(-1)^(n+1)acrsin[(1+√33)/8]+πnx=π/3+(-1)^(n+1)*2acrsin[(1+√33)/8]+2πn,n∈za1=(-1+√33)/8sin(x/2-π/6)=(-1+√33)/8x/2-π/6=(-1)^k*acrsin[(-1+√33)/8]+πkx/2=π/6+(-1)^*acrsin[(-1+√33)/8]+πkx=π/3+(-1)^k*2acrsin[(-1+√33)/8]+2πk,k∈z