Решите уравнение : 2x^4+5x^3-5x-2=0

2x^4 + 5x³ - 5x -2 = 02(x⁴-1) + 5x(x²-1) = 02(x²-1)(x²+1) + 5x(x²-1) = 0(2(x²+1) + 5x)(x²-1) = 0(2x² + 5x + 2)(x²-1) = 0x² - 1 = 0 x = 1; x = -12x²+5x +2 = 0x1 = -2; x2 = 0,5