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Сумма третьего и девятого членов арифметической прогрессии равна 8. Найдите сумму первых 11 членов этой прогрессии
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Предмет:
Алгебра -
Автор:
lianafarrell - 6 лет назад
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Ответы 1
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a₁+2d+a₁+8d=82a₁+10d=8S₁₁=(a₁+a₁₁)/2*11=(a₁+a₁+10d)/2*11=(2a₁+10d)/2*11=8/2*11=44
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Автор:
lukecampbell - 6 лет назад
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0
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Помогите исправить ошибку(не выводит ответ)Ребус ussr+usa=РЕАСЕ
var
m: set of byte;
u,s,r,a,p,e,c: integer;
begin
m := [];
for u := 1 to 6 do
if not (u in m) then
begin
Include(m, u);
for s := 0 to 6 do
if not (s in m) then
begin
Include(m, s);
for r := 0 to 6 do
if not (r in m) then
begin
Include(m, r);
for a := 0 to 6 do
if not (a in m) then
begin
Include(m, a);
for p := 1 to 6 do
if not (p in m) then
begin
Include(m, p);
for e := 0 to 6 do
if not (e in m) then
begin
Include(m, e);
for c := 0 to 6 do
if not (c in m) then
begin
Include(m, c);
if u * 1000 + s * 100 + s * 10 + r +
u * 100 + s * 10 + a =
p * 10000 + e * 1000 + a * 100 + c * 10 + e then
WriteLn(u, s, s, r, ' + ', u, s, a, ' = ', p, e, a, c, e);
Exclude(m, c)
end;
Exclude(m, e);
end;
Exclude(m, p);
end;
Exclude(m, a)
end;
Exclude(m, r)
end;
Exclude(m, s)
end;
Exclude(m, u)
end;
end.-
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