Решите тригонометрическое уравнение: [tex] \sqrt{3} cos ^{2} x -0.5sin2x=0
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[tex]cos ^{2}x+sin2x=0
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1√3cos²x-sinxcosx=0cosx(√3cosx-sinx)=0cosx=0⇒x=π/2+πn,n∈z√3cosx-sinx=0/cosx√3-tgx=0tgx=√3⇒x=π/3+πk,k∈z2cos²x+2sinxcosx=0cosx(cosx+2sinx)=0cosx+2sinx=0/cosx1+2tgx=0tgx=-1/2⇒x=-arctg1/2+πk,k∈zcosx=0⇒x=π/2+πn,n∈z