помогите решить задачку срочно {x-у=2 {у²-2ху=3

According to the first equation，x=y+2,then we put it into the second equation,we get the new equation：у²-2（y+2）y =3у²-2（у²+2y）=3у²-2у²-4y=3-у²-4y=3у²+4y+3=0（y+3）*（y+1）=0y=-3，x=-1 or y=-1，x=1