Решите неравенство: [tex] \frac{2}{ x^{2} +7x+6} \leq \frac{4}{x^{2}+7x+6 } [/tex]

2(x^2+7x+6)<=4(x^2+7X+6)2x^2+14x+12<=4x^2+28x+242x^2-4x^2+14x-28x<=24-12-2x^2-14x<=12-2x(x+7)<=12-2x<=12       x+7=12-x<=6             x<=5x>=-6x[-6;5]