Помогите решить cos2x+3=6sinx*cosx

cos²x-sin²x+3cos²x+3sin²x-6sinxcosx=0/cos²x2tg²x-6tgx+4=0tgx=aa²-3a+2=0a1=a2=3 U a1*a2=2a1=1⇒tgx=1⇒x=π/4+πn,n∈za2=2⇒tgz=2⇒x=arctg2+πk,k∈z