Решите неравенство:[tex] \frac{1}{9} ^{ \frac{4-x^{2} }{2} } \geq 27 ^{x} [/tex]

(3^-2)^[(4-x²)/2]≥(3³)^x3^(x²-4)≥3^3xx²-4≥3xx²-3x-4≥0x1+x2=3 U x1*x2=-4x1=-1 U x2=4x∈(-∞;-1] U [4;∞)