2sin^2x-2sin2x+1=0
решите плиз

2sin^2x-2sin2x+1=02sin^2x-4sinxсosx+sin^2x+cos^2x=03sin^2x-4sinxсosx+cos^2x=03tg^2x-4tgx+1=0tgx=1x=п/4+пktgx=1/3x=arctg(1/3)+пk