найти критические точки функции y=x^5-6x^3 - Дата: 17.10.2019, Автор: arturo - №19085292

найти критические точки функции y=x^5-6x^3
- Предмет:
  Алгебра
- Автор:
  arturo
- 6 лет назад

Ответы 1

$y'= (x^{5} -6 x^{3} )'=5 x^{4} -18 x^{2} ;$ $5 x^{4} -18 x^{2}=0; x^{2} (5 x^{2} -18)=0; x_{1} =0$ $5 x^{2} -18=0; 5 x^{2} =18$ $x^{2} =18/5 x= \sqrt{18} / \sqrt{5}$
- Автор:
  pippin
- 6 лет назад
- 0
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