Решите тригонометрическое уравнение
ctg(x/2+π/3)=√3

Решениеctg(x/2+π/3)=√3x/2+π/3 = arcctg√3 + πk, k ∈ Zx/2+π/3 = π/6 + πk, k ∈ Zx/2 = π/6 - π/3 + πk, k ∈ Zx/2 = - π/6 + πk, k ∈ Zx = - π/3 + 2πk, k ∈ Z