㏒₂(3x-10)=5
㏒₄176-㏒₄2.75

1)log2 (3x-10)=5(loga (x)=y ⇔x=aˇy)3x-10=2ˇ53x-10=323x=32+103x=42x=14====2)log4 176 - log4 2,75=log4 176/2,75=log4  64 =3  (4³=64)Otvet: 3(log x-log y = log x/y)