(30sin11*cos11)/5sin22

По формуле синуса двойного угла
sin2α=2·sinα·cosα.

2·sin11·cos11= sin22.

(30sin11·cos11)/(5sin22) =(15·2·sin11·cos11)/(5sin22) =(15·sin22)/(5sin22)=3

О т в е т.(30sin11·cos11)/(5sin22) =3