2sin (7π/2+x)* sin x =√3 cos x, [-7π;-6π]

2sin(7π/2 + x)*sinx = √3*cosx2sin(π/2 + x)sinx = √3cosx2cosxsinx - √3cosx = 0cosx(2sinx - √3) = 01)  cosx = 0x₁ = π/2 + πk, k∈Z2)  2sinx - √3 = 0sinx = √3/2x = (-1)^(n)*arcsin(√3/2) + 2πn, n∈Zx₂ = (-1)^(n)*(π/3) + 2πn, n∈Z