(x^2-6x+1)^2+6(x^2-6x+1)-7=0 помогите

Пусть x^2 - 6x + 1 = t, тогдаt^2 + 6t - 7 = 0 D = 36 + 28 = 64 = 8^2t1 = ( - 6 + 8)/2 = 1t2 = ( - 6 - 8)/2 = - 7Возвращаемся обратно к замене1) x^2 - 6x + 1 = 1x^2 - 6x = 0 x (x - 6) = 0 x1 = 0 ;x2 = 62) x^2 - 6x + 1 = - 7x^2 - 6x + 8 = 0 D = 36 - 32 = 4 = 2^2x3 = ( 6 + 2)/2 = 4x4 = ( 6 - 2)/2 = 2Ответ4; 2; 0; 6