1) z1=1-і
2) z2=2+3і
найти +,-,*

z1+z2=(1-i)+(2+3i)=(1+2)+i(-1+3)=3+2iz1-z2=(1-i)-(2+3i)=(1-2)+i(-1-3)=-1-4iz1*z2=(1-i)*(2+3i)=2-2i+3i-3i²=2+3+i(-2+3)=5+i