Решите уравнение:
4 x^{2} − 19x+32= − 6 x^{2} − 6x+41

4x²-19x+32=-6x²-6x+4110x²-13x-9=0D=b²-4ac=169+360=529 \sqrt{D}=23 \\ \\ 
 x_{1}= \frac{13-23}{20}=-0,5 \\ \\ 
 x_{2}=\frac{13+23}{20}= \frac{36}{20}=\frac{9}{5}=1,8 \\ \\ Ответ:-0,5;1,8.

4x^2 - 19x + 32 = - 6x^2 - 6х + 41 4х^2 + 6х^2 - 19х + 6х + 32 - 41 = 0 10х^2 - 13х - 9 = 0 D = 169 + 360 = 529 = 23^2 X1 = ( 13 + 23 ) : 20 = 1,8X2 = ( 13 - 23 ) : 20 = - 0,5