Решите неравенства:
а)(x^2-25)*(x^2-x-30)≤0
б)(16x^4-x^2)(-x^2-10)≤0

a) (x²-25)(x²-x-30)≤0x²-25=(x-5)(x+5)x²-x-30=0   D=121x₁=6   x₂=-5(x-6)(x+5)=0   ⇒(x-5)(x+5)(x-6)(x+5)≤0(x-5)(x+5)²(x-6)≤0-∞_____+____(-5)____+_____5____-_____6_____+_____+∞x∈(-5)U(5;6).b) (16x⁴-x²)(-x²-10)≤0(16x⁴-x²)(x²+10)≥0x²(16x²-1)(x²+10)≥0   x²(4x-1)(4x+1)(x²+10)≥0x²≥0    x²+10>0   ⇒-∞_______+_______-1/4___-____(0)__-____1/4_______+______+∞x∈(-1/4;1/4).