(3x-15)/x^2+5x-14>=0

(3x-15)/(x²+5x-14)≥0
x²+5x-14=0   D=81
x₁=2    x₂=-7
3(x-5)/((x-2)(x+7))≥0    |÷3         ОДЗ:   x≠2        x≠-7
(x-5)/((x-2)(x+7)≥0
-∞_____-______-7______+______2_____-______5_____+_____+∞
x∈(-7;2)U[5;+∞).