помогите решить
(x-2)(x-3)=x (x+1)
(x+4)(x+6)-x2=30
(x-5)(x+1)-x=x2+5
(x-1)(x-3)=(x-2 )(x-4)

1) x^2-3x-2x+6=x^2+x

-6x=-6

x=1

2)x^2+6x+4x+24-x^2=30

10x=6

x=0,6

3)x^2+x-5-5x-x=x^2+5

-5x=10

x=-2

4)x^2-3x-x+3=x^2-4x-2x+8

2x=5

x=2,5

(x-2)(x-3)=x(x+1)                (x+4)(x+6)-x^2=30                      (x-5)(x+1) -x=x^2+5

x^2-3x-2x+6=x^2+x            x^2+6x+4x+24-x^2-30=0          x^2+x-5x-5-x-x^2=5

x^2-5X+6-x^2-x=0                    10x=6                                        5x=10

4x=-6                                        x=0,6                                    x=2

x=-1,5

(x-1)(x-3)=(x-2)(x-4)

x^2-3x-x+3=x^2-4x-2x+8

x^2-4x-x^2+6x=8-3

2x=5

x=2,5