Сократите дробь 12^(n+2)/(2^(n+5))*(3^(n-1))

(12n+24):(2n+10)×(3n-3)=12n+24:(6n2-6n+30n-30)=(6n2+24n-30):(12n+24)=n (6n-6):12 (n+1)=6n (n+1):12 (n+1)=(6n:12)×(n+1)