Докажите тождество :(5x/x-10+20x/x2-20x+100):4x-24/x2-100-25x\x-10=5x\4

1)5x/(x-10)+20x/(x-10)²=(5x²-50x+20x)/(x-10)²=(5x²-30x)/(x-10)²==5x(x-6)/(x-10)²2)5x/(x-10)² *(x-10)(x+10)/4(x-6)=(5x²+50x)/4(x-10)3)(5x²+50x)/4(x-10)-25/(x-10)=(5x²+50x-100x)/4(x-10)==(5x²-50x)/4(x-10)=5x(x-10)/4(x-10)=5x/4