Решите систему уравнений {2х+у=1, х^2-11х+14=2у

2х + y = 1 X^2 - 11x + 14 = 2y ••••••••y = 1 - 2x 2y = 2 - 4x 2 - 4x = x^2 - 11x + 14 X^2 - 7x + 12 = 0 D = 49 - 48 = 1 X1 = ( 7 + 1 ) : 2 = 4 X2 = ( 7 - 1 ) : 2 = 3 •••••••••y = 1 - 2x y1 = 1 - 8 = - 7 y2 = 1 - 6 = - 5 Ответ ( 4 ; - 7 ) ; ( 3 ; - 5 )