1)sin156*cos24*+cos156*sin24*= 2)cos81*cos51*+sin81*sin129*= - №20757111

1)sin156*cos24*+cos156*sin24*=
2)cos81*cos51*+sin81*sin129*=
- Предмет:
  Алгебра
- Автор:
  honey9
- 5 лет назад

Ответы 1

$1)\;sin156^ocos24^o+cos156^osin24^o=sin(156^o+24^o)=sin180^o=0;\\ 2)\;cos81^ocos51^o+sin81^osin129^o=\\=cos(90^o-9^o)cos51^o+sin(90^o-9^o)sin(180^o-51^o)=\\=sin9^o81^ocos51^o+cos9^osin51^o=sin(9^o+51^o)=sin60^o=\frac{\sqrt3}{3}.$
- Автор:
  guzmánaguilar
- 5 лет назад
- 0
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