1log(2)(2x-2)>log(2)(6-5x{2x-2>0⇒2x>2⇒x>1{6-5x>0⇒5x<6⇒x<1,2{2x-2>6-5x⇒7x>8⇒x>1 1/7x∈(1;1 1/7)2log(1/2)(5x-8)>1{5x-8>0⇒5x>8⇒x>1,6{5x-8<0,5⇒5x<8,5⇒x<1,7x∈)1,6;1,7)3log(π)[(x-2)/(x-3)]<log(π)3(x-2)/(x-3)>0x=2 x=3x<2 U x>3(x-2)/(x-3)<3(x-2)/(x-3)-3<0(x-2-3x+9)/(x-3)<0(7-2x)/(x-3)<0x=3,5 x=3x<3 U x>3,5x∈(-∞;2) U (3,5;∞)4log(1/2)(2x-2)≥0{2x-2>0⇒x>1{2x-2≤1⇒x≤1,5x∈(1;1,5]5log(4)x+log(4)(x-3)<1{x>0{x-3>0⇒x>3{log(4)(x²-3x)<1⇒x²-3x<4⇒x²-3x-4<0⇒-1<x<4x1+x2=3 U x1*x2=-4⇒x1=-1 U x2=4x∈(3;4)