Методом подстановки.
x2-3y=1
x-2y=1
Помогите пж

x2-3y=1x=1+2y(1+2y)2-3y=11+4y+4y2-3y-1=04y2+y=0y(4y+1)=0y=0  y=-1/4x=1  x=1/2

х^2-3y=1x=1+2y(1+2y)^2-3y=1x=1+2y1+4y+4y^2-3y=1x=1+2y4y^2+y=0x=1+2yy(4y+1)=0x=1+2yy1=04y+1=0x=1+2yy1=04y=-1x=1+2yy1=0y2= -(1/4)x1=1+2*0x2=1+2*(-1/4)y1=0y2= -(1/4)x1=1x2=1-1/2y1=0y2= -(1/4)x1=1x2=1/2=0,5